Integrand size = 21, antiderivative size = 192 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac {\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}+\frac {2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{63 d}+\frac {2 a \left (8 a^2-3 b^2\right ) \tan (c+d x)}{21 d}+\frac {4 a \left (8 a^2-3 b^2\right ) \tan ^3(c+d x)}{63 d}+\frac {2 a \left (8 a^2-3 b^2\right ) \tan ^5(c+d x)}{105 d} \]
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Time = 0.15 (sec) , antiderivative size = 192, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {2770, 2940, 2748, 3852} \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {2 a \left (8 a^2-3 b^2\right ) \tan ^5(c+d x)}{105 d}+\frac {4 a \left (8 a^2-3 b^2\right ) \tan ^3(c+d x)}{63 d}+\frac {2 a \left (8 a^2-3 b^2\right ) \tan (c+d x)}{21 d}+\frac {2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac {2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{63 d}+\frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d} \]
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Rule 2748
Rule 2770
Rule 2940
Rule 3852
Rubi steps \begin{align*} \text {integral}& = \frac {\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}-\frac {1}{9} \int \sec ^8(c+d x) (a+b \sin (c+d x)) \left (-8 a^2+2 b^2-6 a b \sin (c+d x)\right ) \, dx \\ & = \frac {\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}+\frac {2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{63 d}+\frac {1}{63} \int \sec ^6(c+d x) \left (6 a \left (8 a^2-3 b^2\right )+10 b \left (4 a^2-b^2\right ) \sin (c+d x)\right ) \, dx \\ & = \frac {2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac {\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}+\frac {2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{63 d}+\frac {1}{21} \left (2 a \left (8 a^2-3 b^2\right )\right ) \int \sec ^6(c+d x) \, dx \\ & = \frac {2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac {\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}+\frac {2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{63 d}-\frac {\left (2 a \left (8 a^2-3 b^2\right )\right ) \text {Subst}\left (\int \left (1+2 x^2+x^4\right ) \, dx,x,-\tan (c+d x)\right )}{21 d} \\ & = \frac {2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac {\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}+\frac {2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{63 d}+\frac {2 a \left (8 a^2-3 b^2\right ) \tan (c+d x)}{21 d}+\frac {4 a \left (8 a^2-3 b^2\right ) \tan ^3(c+d x)}{63 d}+\frac {2 a \left (8 a^2-3 b^2\right ) \tan ^5(c+d x)}{105 d} \\ \end{align*}
Time = 3.29 (sec) , antiderivative size = 299, normalized size of antiderivative = 1.56 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {\sec ^9(c+d x) \left (3440640 a^2 b+409600 b^3+3150 b \left (-147 a^2+23 b^2\right ) \cos (c+d x)-737280 b^3 \cos (2 (c+d x))-308700 a^2 b \cos (3 (c+d x))+48300 b^3 \cos (3 (c+d x))-132300 a^2 b \cos (5 (c+d x))+20700 b^3 \cos (5 (c+d x))-33075 a^2 b \cos (7 (c+d x))+5175 b^3 \cos (7 (c+d x))-3675 a^2 b \cos (9 (c+d x))+575 b^3 \cos (9 (c+d x))+2064384 a^3 \sin (c+d x)+3096576 a b^2 \sin (c+d x)+1376256 a^3 \sin (3 (c+d x))-516096 a b^2 \sin (3 (c+d x))+589824 a^3 \sin (5 (c+d x))-221184 a b^2 \sin (5 (c+d x))+147456 a^3 \sin (7 (c+d x))-55296 a b^2 \sin (7 (c+d x))+16384 a^3 \sin (9 (c+d x))-6144 a b^2 \sin (9 (c+d x))\right )}{10321920 d} \]
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Result contains complex when optimal does not.
Time = 2.43 (sec) , antiderivative size = 230, normalized size of antiderivative = 1.20
method | result | size |
risch | \(-\frac {32 \left (945 i a \,b^{2} {\mathrm e}^{10 i \left (d x +c \right )}+180 b^{3} {\mathrm e}^{11 i \left (d x +c \right )}-1008 i a^{3} {\mathrm e}^{8 i \left (d x +c \right )}-567 i a \,b^{2} {\mathrm e}^{8 i \left (d x +c \right )}-1680 a^{2} b \,{\mathrm e}^{9 i \left (d x +c \right )}-200 b^{3} {\mathrm e}^{9 i \left (d x +c \right )}-672 i a^{3} {\mathrm e}^{6 i \left (d x +c \right )}+252 i a \,b^{2} {\mathrm e}^{6 i \left (d x +c \right )}+180 b^{3} {\mathrm e}^{7 i \left (d x +c \right )}-288 i a^{3} {\mathrm e}^{4 i \left (d x +c \right )}+108 i a \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-72 i a^{3} {\mathrm e}^{2 i \left (d x +c \right )}+27 i a \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}-8 i a^{3}+3 i a \,b^{2}\right )}{315 d \left (1+{\mathrm e}^{2 i \left (d x +c \right )}\right )^{9}}\) | \(230\) |
derivativedivides | \(\frac {-a^{3} \left (-\frac {128}{315}-\frac {\left (\sec ^{8}\left (d x +c \right )\right )}{9}-\frac {8 \left (\sec ^{6}\left (d x +c \right )\right )}{63}-\frac {16 \left (\sec ^{4}\left (d x +c \right )\right )}{105}-\frac {64 \left (\sec ^{2}\left (d x +c \right )\right )}{315}\right ) \tan \left (d x +c \right )+\frac {a^{2} b}{3 \cos \left (d x +c \right )^{9}}+3 a \,b^{2} \left (\frac {\sin ^{3}\left (d x +c \right )}{9 \cos \left (d x +c \right )^{9}}+\frac {2 \left (\sin ^{3}\left (d x +c \right )\right )}{21 \cos \left (d x +c \right )^{7}}+\frac {8 \left (\sin ^{3}\left (d x +c \right )\right )}{105 \cos \left (d x +c \right )^{5}}+\frac {16 \left (\sin ^{3}\left (d x +c \right )\right )}{315 \cos \left (d x +c \right )^{3}}\right )+b^{3} \left (\frac {\sin ^{4}\left (d x +c \right )}{9 \cos \left (d x +c \right )^{9}}+\frac {5 \left (\sin ^{4}\left (d x +c \right )\right )}{63 \cos \left (d x +c \right )^{7}}+\frac {\sin ^{4}\left (d x +c \right )}{21 \cos \left (d x +c \right )^{5}}+\frac {\sin ^{4}\left (d x +c \right )}{63 \cos \left (d x +c \right )^{3}}-\frac {\sin ^{4}\left (d x +c \right )}{63 \cos \left (d x +c \right )}-\frac {\left (2+\sin ^{2}\left (d x +c \right )\right ) \cos \left (d x +c \right )}{63}\right )}{d}\) | \(265\) |
default | \(\frac {-a^{3} \left (-\frac {128}{315}-\frac {\left (\sec ^{8}\left (d x +c \right )\right )}{9}-\frac {8 \left (\sec ^{6}\left (d x +c \right )\right )}{63}-\frac {16 \left (\sec ^{4}\left (d x +c \right )\right )}{105}-\frac {64 \left (\sec ^{2}\left (d x +c \right )\right )}{315}\right ) \tan \left (d x +c \right )+\frac {a^{2} b}{3 \cos \left (d x +c \right )^{9}}+3 a \,b^{2} \left (\frac {\sin ^{3}\left (d x +c \right )}{9 \cos \left (d x +c \right )^{9}}+\frac {2 \left (\sin ^{3}\left (d x +c \right )\right )}{21 \cos \left (d x +c \right )^{7}}+\frac {8 \left (\sin ^{3}\left (d x +c \right )\right )}{105 \cos \left (d x +c \right )^{5}}+\frac {16 \left (\sin ^{3}\left (d x +c \right )\right )}{315 \cos \left (d x +c \right )^{3}}\right )+b^{3} \left (\frac {\sin ^{4}\left (d x +c \right )}{9 \cos \left (d x +c \right )^{9}}+\frac {5 \left (\sin ^{4}\left (d x +c \right )\right )}{63 \cos \left (d x +c \right )^{7}}+\frac {\sin ^{4}\left (d x +c \right )}{21 \cos \left (d x +c \right )^{5}}+\frac {\sin ^{4}\left (d x +c \right )}{63 \cos \left (d x +c \right )^{3}}-\frac {\sin ^{4}\left (d x +c \right )}{63 \cos \left (d x +c \right )}-\frac {\left (2+\sin ^{2}\left (d x +c \right )\right ) \cos \left (d x +c \right )}{63}\right )}{d}\) | \(265\) |
parallelrisch | \(-\frac {2 \left (315 a^{3} \left (\tan ^{17}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+1890 \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{3}+105 a^{2} b +3780 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2} b +13230 \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2} b +8820 \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2} b +8532 \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{2}+270 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{3}+1890 \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{3}+3150 \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{3}+315 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+4788 \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{3}-10 b^{3}+4788 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{3}+90 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{3}+1512 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{2}+1260 \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{2}+945 \left (\tan ^{16}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2} b +4272 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{2}+630 \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{3}+1512 \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{2}+8532 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{2}-5112 \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{3}-5112 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{3}+10658 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{3}-840 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{3}+1260 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{2}-840 \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{3}+1050 \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{3}\right )}{315 d \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{9}}\) | \(474\) |
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Time = 0.28 (sec) , antiderivative size = 146, normalized size of antiderivative = 0.76 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=-\frac {45 \, b^{3} \cos \left (d x + c\right )^{2} - 105 \, a^{2} b - 35 \, b^{3} - {\left (16 \, {\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{8} + 8 \, {\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{6} + 6 \, {\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{4} + 35 \, a^{3} + 105 \, a b^{2} + 5 \, {\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{315 \, d \cos \left (d x + c\right )^{9}} \]
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Timed out. \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\text {Timed out} \]
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Time = 0.18 (sec) , antiderivative size = 145, normalized size of antiderivative = 0.76 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {{\left (35 \, \tan \left (d x + c\right )^{9} + 180 \, \tan \left (d x + c\right )^{7} + 378 \, \tan \left (d x + c\right )^{5} + 420 \, \tan \left (d x + c\right )^{3} + 315 \, \tan \left (d x + c\right )\right )} a^{3} + 3 \, {\left (35 \, \tan \left (d x + c\right )^{9} + 135 \, \tan \left (d x + c\right )^{7} + 189 \, \tan \left (d x + c\right )^{5} + 105 \, \tan \left (d x + c\right )^{3}\right )} a b^{2} - \frac {5 \, {\left (9 \, \cos \left (d x + c\right )^{2} - 7\right )} b^{3}}{\cos \left (d x + c\right )^{9}} + \frac {105 \, a^{2} b}{\cos \left (d x + c\right )^{9}}}{315 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 473 vs. \(2 (180) = 360\).
Time = 0.37 (sec) , antiderivative size = 473, normalized size of antiderivative = 2.46 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=-\frac {2 \, {\left (315 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{17} + 945 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{16} - 840 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{15} + 1260 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{15} + 630 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{14} + 4788 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{13} + 1512 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{13} + 8820 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{12} + 1050 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{12} - 5112 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 8532 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 3150 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{10} + 10658 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 4272 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 13230 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} + 1890 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} - 5112 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 8532 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 1890 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 4788 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 1512 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 3780 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 270 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 840 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 1260 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 90 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 315 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 105 \, a^{2} b - 10 \, b^{3}\right )}}{315 \, {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{9} d} \]
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Time = 5.55 (sec) , antiderivative size = 275, normalized size of antiderivative = 1.43 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {b^3}{9\,d\,{\cos \left (c+d\,x\right )}^9}-\frac {b^3}{7\,d\,{\cos \left (c+d\,x\right )}^7}+\frac {a^2\,b}{3\,d\,{\cos \left (c+d\,x\right )}^9}+\frac {128\,a^3\,\sin \left (c+d\,x\right )}{315\,d\,\cos \left (c+d\,x\right )}+\frac {64\,a^3\,\sin \left (c+d\,x\right )}{315\,d\,{\cos \left (c+d\,x\right )}^3}+\frac {16\,a^3\,\sin \left (c+d\,x\right )}{105\,d\,{\cos \left (c+d\,x\right )}^5}+\frac {8\,a^3\,\sin \left (c+d\,x\right )}{63\,d\,{\cos \left (c+d\,x\right )}^7}+\frac {a^3\,\sin \left (c+d\,x\right )}{9\,d\,{\cos \left (c+d\,x\right )}^9}-\frac {16\,a\,b^2\,\sin \left (c+d\,x\right )}{105\,d\,\cos \left (c+d\,x\right )}-\frac {8\,a\,b^2\,\sin \left (c+d\,x\right )}{105\,d\,{\cos \left (c+d\,x\right )}^3}-\frac {2\,a\,b^2\,\sin \left (c+d\,x\right )}{35\,d\,{\cos \left (c+d\,x\right )}^5}-\frac {a\,b^2\,\sin \left (c+d\,x\right )}{21\,d\,{\cos \left (c+d\,x\right )}^7}+\frac {a\,b^2\,\sin \left (c+d\,x\right )}{3\,d\,{\cos \left (c+d\,x\right )}^9} \]
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